Word frequency with Mapreduce in python
"MapReduce is a programming framework popularized by Google and used to simplify data processing across massive data sets. As people rapidly increase their online activity and digital footprint, organizations are finding it vital to quickly analyze the huge amounts of data their customers and audiences generate to better understand and serve them. MapReduce is the tool that is help"
The algorithm fundamentally boils down to two crisp steps, indeed they are map and reduce
- map (k1,v1) ! list(k2,v2)
- reduce (k2,list(v2)) ! list(v2)
The all famous canonical example of map reduce is as below :
void map(String name, String document): // name: document name // document: document contents for each word w in document: EmitIntermediate(w, "1"); void reduce(String word, Iterator partialCounts): // word: a word // partialCounts: a list of aggregated partial counts int sum = 0; for each pc in partialCounts: sum += ParseInt(pc); Emit(word, AsString(sum));
So all said and done, here is the self explanatory python code :
#
# Copyright [2011] Hemanth.HM
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
import collections
import string
__authors__ = "Hemanth HM <[email protected]>"
__version__ = "1.0"
class MapReduce:
""" Linear implementation of MapReduce.
MapReduce is a software framework introduced by Google.
"""
def map_it(self,lines):
""" Returns a list of lists of the form [word,1]
for each element in the list that was passed.
"""
return [[word, 1] for word in lines]
def sort_it(self,wlist):
""" Returns a list of list of the form [word,[partialcounts]] """
res = collections.defaultdict(list)
map(lambda w: res[w[0]].append(w[1]), wlist)
return res.items()
def map_reduce(self,wlist):
""" Returns a dict with word : count mapping """
results = {}
for res in self.sort_it(self.map_it(wlist)) :
results[res[0]] = sum(res[1])
return results
class SlurpFile:
""" Simple class to get the file contents, after filtering punctuations
Attributes:
fpath: Path to the file name.
"""
def __init__(self,path):
""" Inits the SlurpFile class with path to the file
Args:
path: path to the file that needs to be read.
"""
self.fpath = path
def get_contents(self):
""" Read the files and cleans it by removing the punctuations
and returns a list of words.
"""
with open(self.fpath) as wfile:
return ''.join(ch for ch in wfile.read() if ch not in set(string.punctuation)).split()
mr = MapReduce()
slurp = SlurpFile('/tmp/t')
result = mr.map_reduce(slurp.get_contents())
print result
File contents : hemanth is testing ''''',,,,.;;;; hemanth
Output would be : {'hemanth': 2, 'is': 1, 'testing': 1}
Reference for the algorithm can be downloaded here
Recent blog posts
- watir-webdriver web inspector
- gem list to gemfile
- Packing ruby2.0 on debian.
- Made it into The Guinness Book!
- to_h in ruby 2.0
- Filter elements by pattern jQuery.
- Better HTML password fields for mobile ?
- Grayscale image when user offline
- nth-child CSS pseudo-class Christmas colors
- EventEmitter in nodejs